Saturday, June 6 2020, 22:47 pm
1 +5 +4 c e t c e 4t 1 2 a – University of Michigan

1 +5 +4 c e t c e 4t 1 2 a – University of Michigan

Math 216 / Exam 2 (28 March, 2013) page 2 1.[15 points] For this problem note that the general solution to y′′ +5y′ +4y = 0 is y = c1e−t+c2e−4t …